Fix test and retry
parent
9eb94a565d
commit
c997e4911a
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@ -45,24 +45,16 @@ func newTopic(id string) *topic {
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}
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// Subscribe subscribes to this topic
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func (t *topic) Subscribe(s subscriber, userID string, cancel func()) int {
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max_retries := 5
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retries := 1
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func (t *topic) Subscribe(s subscriber, userID string, cancel func()) (subscriberID int) {
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t.mu.Lock()
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defer t.mu.Unlock()
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subscriberID := rand.Int()
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// simple check for existing id in maps
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for {
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_, ok := t.subscribers[subscriberID]
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if ok && retries <= max_retries {
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subscriberID = rand.Int()
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retries++
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} else {
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for i := 0; i < 5; i++ { // Best effort retry
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subscriberID = rand.Int()
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_, exists := t.subscribers[subscriberID]
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if !exists {
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break
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}
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}
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t.subscribers[subscriberID] = &topicSubscriber{
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userID: userID, // May be empty
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subscriber: s,
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@ -42,12 +42,11 @@ func TestTopic_Keepalive(t *testing.T) {
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require.True(t, to.LastAccess().Unix() <= time.Now().Unix()+2)
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}
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func TestTopic_Subscribe_duplicateID(t *testing.T) {
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func TestTopic_Subscribe_DuplicateID(t *testing.T) {
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t.Parallel()
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to := newTopic("mytopic")
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// fix random seed to force same number generation
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// Fix random seed to force same number generation
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rand.Seed(1)
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a := rand.Int()
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to.subscribers[a] = &topicSubscriber{
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@ -60,11 +59,11 @@ func TestTopic_Subscribe_duplicateID(t *testing.T) {
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return nil
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}
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// force rand.Int to generate the same id once more
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// Force rand.Int to generate the same id once more
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rand.Seed(1)
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id := to.Subscribe(subFn, "b", func() {})
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res := to.subscribers[id]
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require.False(t, id == a)
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require.True(t, res.userID == "b")
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require.NotEqual(t, id, a)
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require.Equal(t, "b", res.userID, "b")
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}
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